2[g(b)+1]=b-2(b^2)

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Solution for 2[g(b)+1]=b-2(b^2) equation: 


Simplifying
2[g(b) + 1] = b + -2(b2)

Multiply g * b
2[bg + 1] = b + -2(b2)

Reorder the terms:
2[1 + bg] = b + -2(b2)
[1 * 2 + bg * 2] = b + -2(b2)
[2 + 2bg] = b + -2(b2)

Solving
2 + 2bg = b + -2b2

Solving for variable 'b'.

Reorder the terms:
2 + -1b + 2bg + 2b2 = b + -2b2 + -1b + 2b2

Reorder the terms:
2 + -1b + 2bg + 2b2 = b + -1b + -2b2 + 2b2

Combine like terms: b + -1b = 0
2 + -1b + 2bg + 2b2 = 0 + -2b2 + 2b2
2 + -1b + 2bg + 2b2 = -2b2 + 2b2

Combine like terms: -2b2 + 2b2 = 0
2 + -1b + 2bg + 2b2 = 0

The solution to this equation could not be determined.

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